Let’s solve the problem step-by-step.

Let’s call the unknown number $x$.

The problem states that the sum of twice a number and half the number is 10. In mathematical terms, this can be written as:

2x+x2=102x + \frac{x}{2} = 102x+2x​=10To solve for $x$, first let’s clear the fraction by multiplying every term by 2:

2(2x)+2(x2)=2(10)2(2x) + 2\left(\frac{x}{2}\right) = 2(10)2(2x)+2(2x​)=2(10)This simplifies to:

$$4x+x=20$$Combine like terms:

$$5x=20$$Now, divide both sides by 5:

x=205=4x = \frac{20}{5} = 4x=520​=4So, the number is $x=4$.

Answer: The number is 4.